KCSE MATHEMATICS QUESTIONS AND SOLUTIONS ~ Topically Analyzed
Comprehensive Answers and Marking Schemes KNEC Certified
In the figure below, ABCDEF is a regular polygon. Line AB and EC are each extended to meet at G11/2/2024 ALT B  ANGLES AND PLANE FIGURES  SECTION 1  QUESTION 6  KCSE 2010  FORM 1 LEVELIn the figure below, ABCDEF is a regular polygon. Line AB and EC are each extended to meet at G. Calculate the size of angle BGC. (3 marks)
0 Comments
ALT B  LOGARITHMS  SECTION 1  QUESTION 5  KCSE 2010  FORM 2 LEVELUse logarithms to evaluate (43.2 X 0.015) / ∛0.00679 (4 marks)
ALT B  AREA OF A RECTANGLE  SECTION 1  QUESTION 4  KCSE 2010  FORM 2 LEVELThe length of a rectangular floor of a hall is 35.2m. If the diagonal of the floor is 37.7m, Calculate the area of the floor. (3 marks)
ALT B  ALGEBRA & INTEGERS  SECTION 1  QUESTION 3  KCSE 2010  FORM 1 LEVELGiven that x = 2, y = 3 and z = 5, evaluate [2x + 3 (y + z)] / 4yz. (2 marks)
ALT B  SQUARES & SQUARE ROOTS  SECTION 1  QUESTION 2  KCSE 2010  FORM 1 LEVELUse the prime factors of 7056 to find √7056 (2 marks)
ALT B  BODMAS  SECTION 1  QUESTION 1  KCSE 2010  FORM 1 LEVELWithout using a calculator, evaluate: 270 ÷ (90 x 2) + 7 x 440 ÷ 5. (2 marks)
â€‹A commercial bank buys and sells Japanese Yen in Kenya Shillings at the rates shown below.7/1/2024 COMMERCIAL ARITHMETIC I  KCSE 1997  FORM 1 LEVEL  PAPER 2  SECTION AA commercial bank buys and sells Japanese Yen in Kenya Shillings at the rates shown below. A Japanese tourist at the end of his tour of Kenya was left with Kshs. 30,000 which he converted to Japanese Yen through the commercial bank. How many Japanese Yen did he get? KNEC ANSWERS
Given that 1 Japanese Yen is selling at Ksh 0.5446, we can use this rate to calculate the amount of Japanese Yen the tourist received.
The tourist had Kshs 30,000, so we can calculate the amount of Japanese Yen as follows: Amount in Japanese Yen = Kshs 30,000 ÷ Selling rate of 1 Japanese Yen Amount in Japanese Yen = Kshs 30,000 ÷ 0.5446 The calculation gives us: Amount in Japanese Yen ≈ 55,082.12 Therefore, the tourist received approximately 55,082 Japanese Yen. kcse 1996  paper 1  section a  question 3  commercial arithmetic  form 1 levelThe cost of 5 skirts and 3 blouses is Kshs 1750. Mueni bought three of the skirts and one of the blouses for Kshs 850. Find the cost of each item (3 marks).
QUESTION 16  KCSE 2023  3d geometry  PAPER 2  FORM 3 LEVELP, Q and R are points on a level ground. Q is 4.5 m south of P. R is to the east of P and 5.3 m from Q. A vertical post at P is supported by a cable of length 3.5 m. The cable joins the top T of the post to point R.
Calculate the angle between the cable and the level ground correct to 2 decimal places. (3 marks) QUESTION 15  KCSE 2023  differentiation  PAPER 2  FORM 4 LEVELThe gradient function of a curve is given by dy/dx = 3  4x. If the curve passes through the point (1, 10), find the equation of the curve. (3 marks)
QUESTION 14  KCSE 2023  LINEAR MOTION  PAPER 2  FORM 3 LEVELA stone was thrown upwards from a point 8 metres above the ground. The following graph shows the height, h metres of the stone above the ground at time / seconds in the interval 0 ≤ t ≤ 4. Determine the rate of change of h at t = 2 seconds. (3 marks)
QUESTION 13  KCSE 2023  FORMULA & VARIATIONS  PAPER 2  FORM 3 LEVELA quantity v varies directly as the square of u and inversely as the cube root of w. When u = 5 and w = 8, the value of' v = 375. Find the value of v when u = 8 and w = 125. (3 marks)
QUESTION 12  KCSE 2023  QUADRATIC EQUATIONS  PAPER 2  FORM 4 LEVELThe length and width of a rectangular floor of a room are 10 m and 7 m respectively. A rectangular carpet of area 28 m² is placed on the floor. The carpet leaves a uniform space of x m with each of the walls of the room.
Form a quadratic equation in x and hence solve for x. (3 marks) QUESTION 11  KCSE 2023  MATRICES & TRANSFORMATION  PAPER 2  FORM 4 LEVEL
A transformation matrix T = [1 0] [k 0] maps P(2, 3) onto P'(2, 10). Point Q(4, 4) is transformed under the same matrix T. Find the coordinates of Q', the image of Q. (3 marks)
T = \begin{pmatrix} 1 & 0 \\ K & 0 \\ \end{pmatrix}
QUESTION 10  KCSE 2023  COMMERCIAL ARITHMETIC II  PAPER 2  FORM 3 LEVELThe following table shows monthly income tax rates of a certain year. In that year, a monthly relief of Ksh 2 400 was allowed. The net tax on Lesianto's monthly income was Ksh 1 500.
Calculate Lesianto's monthly income. (3 marks) QUESTION 9  KCSE 2023  GRAPHICAL METHODS  PAPER 2  FORM 3 LEVELThe following figure shows a circle centre O.
Given thatÂ pÂ = 5iÂ Â jÂ + 3k,Â qÂ = 8iÂ +Â jÂ andÂ rÂ = 2pÂ Â q, determine the magnitude ofÂ r1/1/2024 QUESTION 8  KCSE 2023  VECTORS II  PAPER 2  FORM 3 LEVELGiven that p = 5i  j + 3k, q = 8i + j and r = 2p  q, determine the magnitude of r. (3 marks)
The following table shows the frequency distribution of marks scored by 40 students in a test1/1/2024 QUESTION 7  KCSE 2023  STATISTICS II  PAPER 2  FORM 4 LEVELThe following table shows the frequency distribution of marks scored by 40 students in a test. Calculate the upper quartile mark. (3 marks)
QUESTION 6  KCSE 2023  TRIGONOMETRY II  PAPER 2  FORM 3 LEVELSolve 6cos²(x) = 5sin(x) for 0≤x≤ 180°. (4 marks)
QUESTION 5  KCSE 2023  LONGITUDES & LATITUDES  PAPER 2  FORM 4 LEVELA plane took 3 hours to fly from P(66.42°N, 30°E) to Q(66.42°N, 52.5°E). Determine the speed of the plane in knots correct to one decimal place. (3 marks)
QUESTION 4  KCSE 2023  CIRCLES, CHORDS AND TANGENTS  PAPER 2  FORM 3 LEVELIn this question, use a ruler and a pair of compasses. The following figure shows a circle, centre O. A tangent to the circle at P is drawn. Construct another tangent to the circle to intersect the drawn tangent at an angle of 60°. (3 marks)
QUESTION 3  KCSE 2023  Formula & Variations  PAPER 2  FORM 3 LEVELQUESTION 2  KCSE 2023  Approximation & Errors  PAPER 2  FORM 3 LEVELThe masses of two students in a class were measured as 30.5 kg and 36.8 kg. Determine the least possible difference in the masses of the two students. (3 marks)
QUESTION 1  KCSE 2023  INDICES & LOGARITHMS  PAPER 2  FORM 2 LEVELSolve the equation 1 + log(2x – 9) = log(3x + 5)  log 2. (3 marks)
QUESTION 16  KCSE 2023  GRAPHICAL METHODS  PAPER 1  FORM 3 LEVELOn the following cartesian plane provided, solve the simultaneous equations.
y = 4/3 x + 2; 3y = x  3 
Categories
All
Archives
January 2025
Latest Posts 
Primary Resources
College Resources
Can't find what you want? Use this Search box. 
Secondary Resources

Contact Us
Manyam Franchise
P.O Box 1189  40200 Kisii Tel: 0728 450 424 Tel: 0738 619 279 Email  sales@manyamfranchise.com 